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-0.6x^2-3x+8.4=0
a = -0.6; b = -3; c = +8.4;
Δ = b2-4ac
Δ = -32-4·(-0.6)·8.4
Δ = 29.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{29.16}}{2*-0.6}=\frac{3-\sqrt{29.16}}{-1.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{29.16}}{2*-0.6}=\frac{3+\sqrt{29.16}}{-1.2} $
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